排名

用户解题统计

过去一年提交了

勋章 ①金银铜:在竞赛中获得第一二三名;②好习惯:自然月10天提交;③里程碑:解决1/2/5/10/20/50/100/200题;④每周打卡挑战:完成每周5题,每年1月1日清零。

收藏

收藏日期 题目名称 解决状态
没有收藏的题目。

评论笔记

评论日期 题目名称 评论内容 站长评论
没有评论过的题目。

提交记录

提交日期 题目名称 提交代码
2025-12-22 条件过滤(2)半夜活动有猫腻,Hour函数给给力 
SELECT *
FROM cmb_usr_trx_rcd
WHERE usr_id = 5201314520
AND trx_time >= '2024-09-01'
AND trx_time < '2024-10-01'
AND HOUR(trx_time) >= 1
AND HOUR(trx_time) < 6
ORDER BY trx_time ASC;
2025-12-22 条件过滤(1)异地男友有异常,数分闺蜜来帮忙 
SELECT *
FROM cmb_usr_trx_rcd
WHERE usr_id = 5201314520
AND trx_time >= '2024-09-01'
AND trx_time < '2024-10-01'
ORDER BY trx_time ASC;
2025-12-21 分组与聚合函数(2)擦边营收怎么样,聚合函数可看出 
SELECT 
DATE(trx_time) AS trx_date,
MAX(trx_amt) AS max_trx_amt,
MIN(trx_amt) AS min_trx_amt,
AVG(trx_amt) AS avg_trx_amt,
SUM(trx_amt) AS total_trx_amt
FROM cmb_usr_trx_rcd
WHERE mch_nm = '红玫瑰按摩保健休闲'
AND trx_time >= '2024-09-01'
AND trx_time < '2024-10-01'
GROUP BY DATE(trx_time)
ORDER BY trx_date ASC;
2025-12-21 分组与聚合函数(1)Money全都花在哪,GroupBy来查一查 
select mch_nm, sum(trx_amt) AS sum_trx_amt
from cmb_usr_trx_rcd
where usr_id=5201314520 AND year(trx_time) = 2024
group by mch_nm
order by sum_trx_amt desc
;
2025-12-21 分组与聚合函数(1)Money全都花在哪,GroupBy来查一查 
select mch_nm, sum(trx_amt) AS sum_trx_amt
from cmb_usr_trx_rcd
where usr_id=5201314520
group by mch_nm
order by sum_trx_amt desc
;
2025-12-21 分组与聚合函数(1)Money全都花在哪,GroupBy来查一查 
select mch_nm, sum(trx_amt) AS sum_trx_amt
from cmb_usr_trx_rcd
where usr_id=5201314520
group by mch_nm
;