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过去一年提交了

勋章 ①金银铜:在竞赛中获得第一二三名;②好习惯:自然月10天提交;③里程碑:解决1/2/5/10/20/50/100/200题;④每周打卡挑战:完成每周5题,每年1月1日清零。

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评论日期 题目名称 评论内容 站长评论
2024-12-04 时间日期(2)按月统计日花费,一天都不要浪费 
select trx_mon,last_day,day(last_day) as days_of_mon
from (select DATE_FORMAT(date(trx_time),'%Y-%m') as trx_mon, last_day(trx_time) as last_day
	from cmb_usr_trx_rcd
	where usr_id=5201314520 and year(trx_time) in (2023,2024)
	group by trx_mon,last_day
	order by trx_mon) a
哪里有bug呀,提交不通过呢,运行得出的结果也正常
啥也没说

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提交日期 题目名称 提交代码
2024-12-22 字符串与通配符(2)好多关键词做规则,可以使用rlike 
select 
	case 
	when mch_nm like '%按摩保健休闲%' then '按摩保健休闲'
when upper(mch_nm) rlike '.*(按摩|保健|休闲|养生|SPA|会所).*' then'按摩、保健、休闲、养生、SPA、会所'
end as reg_rules,
count(distinct mch_nm) as mch_cnt
from cmb_usr_trx_rcd 
where mch_nm like '%按摩保健休闲%' 
	or upper(mch_nm)rlike '.*(按摩|保健|休闲|养生|SPA|会所).*'
group by reg_rules
order by mch_cnt desc;
2024-12-22 热门搜索关键词 
select key_word ,count(*) as search_count
from jx_query_rcd
group by key_word
order by search_countdesc
limit 5
2024-12-07 德州扑克起手牌- 手对 
select * 
from hand_permutations 
where left(card1,1)=left(card2,1)
order by id
2024-12-07 德州扑克起手牌- A花 
select * 
from hand_permutations
where right(card1,1)=right(card2,1) and
(card1 like 'A%' or card2 like 'A%')
order by id
2024-12-07 德州扑克起手牌-最强起手牌KK+ 
select *
from hand_permutations
where concat(substr(card1,1,1),substr(card2,1,1)) in ('AA','KK','AK','KA')
2024-12-03 表连接(2)渣男去过我对象没去过,那就用LeftJoin 
select a.mch_nm as asshole_tried ,a.trx_cnt,b.mch_nm as darling_tried
from
(select mch_nm,count(mch_nm)as trx_cnt
from cmb_usr_trx_rcd
where usr_id='5201314520' and year(trx_time) in (2023,2024) 
group by mch_nm
having count(mch_nm)>=20 )a
left join
(select distinct mch_nm
from cmb_usr_trx_rcd
where usr_id='5211314521' and year(trx_time) in (2023,2024) )b
on a.mch_nm=b.mch_nm
order by trx_cnt desc
2024-12-03 表连接(1)你们难道都去过?那就试试用InnerJoin 
select a.* from 
(select distinct mch_nm
from cmb_usr_trx_rcd
where year(trx_time)=2024 and usr_id='5211314521')a
inner join
(select distinct mch_nm
from cmb_usr_trx_rcd
where year(trx_time)=2024 and usr_id='5201314520')b
on a.mch_nm = b.mch_nm
order by 1 desc
2024-12-03 表连接(1)你们难道都去过?那就试试用InnerJoin 
select distinct t1.mch_nm 
from cmb_usr_trx_rcd t1
inner join
	(select *
	from cmb_usr_trx_rcd 
	where usr_id=5211314521) t2
on t1.mch_nm=t2.mch_nm
where t1.usr_id=5201314520 and year(t1.trx_time)=2024
order by mch_nm desc
2024-12-03 子查询(1)玩的最嗨那天在做甚?要用Where子查询 
select usr_id,mch_nm,trx_time,trx_amt
from cmb_usr_trx_rcd 
where usr_id=5201314520 and year(trx_time)=2024
order by trx_amt desc
limit 1
2024-12-03 字符串与通配符(1)名称里面有特服,可以使用通配符 
select count(distinct mch_nm) as mch_nm
from cmb_usr_trx_rcd 
where mch_nm like '%按摩保健休闲%'
2024-12-03 分类(1)姿势太多很过分,分类要用CaseWhen 
select 
case 
when trx_amt=288 then '1.WithHand'
when trx_amt=388 then '2.WithMimi'
when trx_amt=588 then '3.BlowJobbie'
when trx_amt=888 then '4.Doi'
when trx_amt=1288 then '5.DoubleFly'
else '6.other'
end as ser_typ
,count(1) as trx_cnt,
	min(date(trx_time)) as first_date
from cmb_usr_trx_rcd 
where usr_id='5201314520' and mch_nm='红玫瑰按摩保健休闲'
group by ser_typ
order by 1
2024-12-03 分组与聚合函数(6)想知道渣男有多坏,疯狂使用GroupBy 
select usr_id,mch_nm,sum(trx_amt) as trx_amt, count(*) as trx_cnt,
	min(trx_time) as first_time
from cmb_usr_trx_rcd 
where usr_id='5201314520' and trx_amt>=288
group by mch_nm
order by trx_cnt desc
2024-12-03 分组与聚合函数(5)想知道何时成瘾,用Max Or Min? 
select usr_id,min(trx_time) as first_time,mch_nm
from cmb_usr_trx_rcd 
where usr_id='5201314520' and mch_nm='红玫瑰按摩保健休闲'
2024-12-03 分组与聚合函数(5)五花八门的项目,其实都有固定套路(2) 
select trx_amt,
	count(trx_amt) as total_trx_cnt,
	count(distinct usr_id) as unique_usr_cnt,
count(trx_amt)/count(distinct usr_id) as avg_trx_per_user
from cmb_usr_trx_rcd 
where 
	mch_nm='红玫瑰按摩保健休闲' 
and (year(trx_time)= 2023 and month(trx_time) between 1 and 12
or (year(trx_time)= 2024 and month(trx_time) between 1 and 6) )
group by trx_amt
order by avg_trx_per_user desc
limit 5
2024-12-03 分组与聚合函数(5)五花八门的项目,其实都有固定套路(2) 
select trx_amt,
	count(trx_amt) as total_trx_cnt,
	count(distinct usr_id) as unique_usr_cnt,
count(trx_amt)/count(distinct usr_id) as avg_trx_per_user
from cmb_usr_trx_rcd 
where mch_nm='红玫瑰按摩保健休闲' and trx_time between '2023-01-01' and '2024-06-30'
group by trx_amt
order by avg_trx_per_user desc
limit 5
2024-12-03 分组与聚合函数(3)五花八门的项目,其实都有固定套路(1) 
select trx_amt,count(trx_amt) as trx_cnt
from cmb_usr_trx_rcd 
where 
	mch_nm = '红玫瑰按摩保健休闲' 
and date(trx_time) between '2024-01-01' and '2024-07-31'
group by trx_amt
order by trx_cnt desc
limit 5
2024-12-03 分组与聚合函数(2)擦边营收怎么样,聚合函数可看出 
select
    date(trx_time) as trx_date, 
    max(trx_amt) as max_trx_amt, 
    min(trx_amt) as min_trx_amt, 
    avg(trx_amt) as avg_trx_amt, 
    sum(trx_amt) as total_trx_amt 
from
    cmb_usr_trx_rcd
where
    mch_nm = '红玫瑰按摩保健休闲' 
    and date(trx_time) between '2024-09-01' and '2024-09-30' 
group by
    date(trx_time) 
order by
    trx_date;
2024-12-03 分组与聚合函数(1)Money全都花在哪,GroupBy来查一查 
select mch_nm,sum(trx_amt)as sum_trx_amt
from cmb_usr_trx_rcd 
where year(trx_time)=2024 and usr_id=5201314520
group by mch_nm
order by sum(trx_amt) desc
2024-12-03 条件过滤(3)Hour函数很给力,组合条件要仔细 
select * from cmb_usr_trx_rcd
where usr_id=5201314520 and date(trx_time) between '2024-09-01' and '2024-09-30'and( hour(trx_time) between 22 and 24 or hour(trx_time) between 0 and 5 )
order by trx_time
2024-12-03 条件过滤(2)半夜活动有猫腻,Hour函数给给力 
select * 
from cmb_usr_trx_rcd 
where usr_id=5201314520 and DATE(trx_time) between '2024-09-01' and '2024-09-30' and hour(trx_time) between '01:00:00' and'05:00:00'
order by trx_time asc