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勋章 ①金银铜：在竞赛中获得第一二三名；②好习惯：自然月10天提交；③里程碑：解决1/2/5/10/20/50/100/200题；④每周打卡挑战：完成每周5题，每年1月1日清零。

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提交日期 题目名称 提交代码
2026-01-16 渣男腰子可真行，端午中秋干不停  
select * from cmb_usr_trx_rcd 
whereusr_id = '5201314520' and (date(trx_time) between '2024-06-08' and '2024-06-10'
or date(trx_time) between '2024-09-15' and '2024-09-17');
2026-01-16 渣男腰子可真行，端午中秋干不停  
select * from cmb_usr_trx_rcd 
whereusr_id = '5201314520' and date(trx_time) between '2024-06-08' and '2024-06-10'
or date(trx_time) between '2024-09-15' and '2024-09-17';
2026-01-16 条件过滤（2）半夜活动有猫腻，Hour函数给给力  
select * from cmb_usr_trx_rcd 
where usr_id = '5201314520' and date(trx_time) between '2024-09-01' and '2024-09-30' and hour(trx_time) between 1 and 5
order by trx_time;
2026-01-16 条件过滤（1）异地男友有异常，数分闺蜜来帮忙  
select * from cmb_usr_trx_rcd 
where usr_id = '5201314520' and date(trx_time) between '2024-09-01' and '2024-09-30';
2025-02-26 学生信息和班主任姓名  
select s1.name, s1.class_code, s1.grade_code, t1.name head_teacher_name 
from students s1
inner join teachers t1
on s1.class_code = t1.head_teacher
;
2025-02-22 必过(3, -8)的一元一次函数  
select 
    * 
from 
    numbers_for_fun 
where 
    a=0 and (3*b+c)= -8 and b<>0
order by id
2025-02-22 必过(-1, -1)的一元一次函数  
select 
    * 
from 
    numbers_for_fun 
where 
    a=0 and (c-b)= -1 and b<>0
order by id
2025-02-22 必过(0, 1)的一元一次函数  
select 
    * 
from 
    numbers_for_fun 
where 
    a=0 and (0*b + 1*c)=1 and b<>0
order by id
2025-02-22 不经过第二象限的一元一次函数  
select 
    * 
from 
    numbers_for_fun 
where 
    a=0 and b>0 and c<=0
order by id;
2025-02-22 不经过第三象限的一元一次函数  
select 
    * 
from 
    numbers_for_fun 
where 
    a=0 and b<0 and c>=0
order by id
;
2025-01-26 总分超过300分的学生  
select student_id from subject_score 
where chinese + math + english >= 300;
2025-01-26 找出与y=x有交点的所有一元一次函数  
select * from numbers_for_fun
where a= 0 and b!=1 and b!=0
order by id;
2025-01-26 找出与X轴交点小于等于0的一元一次函数  
select * from numbers_for_fun 
where a = 0 and b!=0 and b*c>=0;
2025-01-26 找出与X轴交点大于0的一元一次函数  
select * from numbers_for_fun 
where a = 0 and b!=0 and b*c<0
order by id;
2025-01-26 找出与X轴交点大于0的一元一次函数  
select * from numbers_for_fun 
where a = 0 and b!=0 and b*c>0
order by id;
2025-01-26 找出与X轴交点大于0的一元一次函数  
select * from numbers_for_fun 
where a = 0 and b!=0 and c>0
order by id;
2025-01-26 找出与X轴交点大于0的一元一次函数  
select * from numbers_for_fun 
where a = 0 and b!=0 and c!=0
order by id;
2025-01-26 找出所有经过原点的一元一次函数  
select * from numbers_for_fun 
where a=0 and b!=0 and c=0
order by id;
2025-01-26 找出所有一元一次函数  
select * from numbers_for_fun 
where a = 0 and b!= 0
order by id;
2025-01-15 输出特定日期上市的银行  
select * from stock_info 
where list_date between '2006-06-01' and '2006-09-01'
and industry = "银行";