排名

用户解题统计

过去一年提交了

勋章 ①金银铜:在竞赛中获得第一二三名;②好习惯:自然月10天提交;③里程碑:解决1/2/5/10/20/50/100/200题;④每周打卡挑战:完成每周5题,每年1月1日清零。

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收藏日期 题目名称 解决状态
2025-06-13 多云天气天数  已解决
2025-06-13 城市平均最高气温  已解决
2025-06-13 至少两门科目大于等于110分的学生  未解决
2025-06-12 只买iPhone的用户  已解决
2025-06-12 基于共同兴趣爱好的餐厅推荐(6)-好基友(5)  已解决
2025-06-12 基于共同兴趣爱好的餐厅推荐(5)-好基友(3)  已解决
2025-06-12 基于共同兴趣爱好的餐厅推荐(4)-好基友(2)  已解决
2025-06-12 基于共同兴趣爱好的餐厅推荐(3)-好基友(1)  已解决
2025-06-08 数学成绩分段统计(3)  未解决
2025-06-08 数学成绩分段统计(2)  已解决
2025-06-08 各班第一名  已解决
2025-06-08 各商品漏斗转化率  已解决
2025-06-08 统计每个城市各状态的单量(行转列)  已解决
2025-06-08 先收藏后购买的用户数  已解决
2025-06-08 登录天数分布  未解决
2025-06-07 给商品打四类标签(列)  已解决
2025-06-07 给商品打四类标签(行)  已解决
2025-06-07 每年地产与软件服务上市公司对比  已解决
2025-06-07 一线城市历年平均气温  已解决
2025-06-07 从未被领取的优惠券  已解决
2025-06-06 拼接歌曲名和专辑名  已解决
2025-06-06 歌曲流行度分析  已解决
2025-06-06 用户听歌完成情况  已解决
2025-06-05 专辑播放量统计  已解决
2025-06-05 最受欢迎歌手  已解决
2025-06-05 用户听歌多元化标签  已解决
2025-06-05 MJ最受欢迎的歌曲  已解决
2025-06-05 周杰伦的最受欢迎的专辑  已解决
2025-06-05 计算视频的平均观看完成率  已解决
2025-06-01 各行业第一家上市公司  已解决
2025-05-31 平均分最高的班级  已解决
2025-05-31 红包发送量排名  已解决
2025-05-31 统计每个城市各状态的单量  已解决
2025-05-30 找出北京和柳州单量最多的司机  已解决
2025-05-30 窗口函数(4)越来越喜欢召妓,窗口函数用累计(2)  未解决
2025-05-29 窗口函数(3)越来越喜欢召妓,窗口函数用累计(1)  已解决
2025-05-29 时间日期(4)阶段综合-按月统计日花费,一天都不要浪费  已解决
2025-05-29 时间日期(2)按月统计日花费,一天都不要浪费  已解决
2025-05-29 表连接(5)哪些没被分出来,用左用内你来猜  已解决
2025-05-29 表连接(4)渣男把钱花在哪儿,维表可以来帮忙  已解决
2025-05-28 查询播放量为0的歌手及其专辑  已解决
2025-05-28 用户听歌习惯的时间分布  已解决
2025-05-28 找出酒店-餐饮的最热门路线  已解决
2025-05-28 查询所有以住宅区为起点且以写字楼为终点的行程  已解决
2025-05-28 查询所有起点和终点都属于餐饮类别的行程  已解决
2025-05-28 查询所有终点是餐饮类地点的行程记录  已解决
2025-05-27 曝光量最大的商品  已解决
2025-05-27 只被收藏未被购买的商品  已解决
2025-05-27 被收藏次数最多的商品  已解决
2025-05-27 不分类别的最火直播间  已解决
2025-05-26 文科潜力股  已解决
2025-05-26 找出三个班级的女生  已解决
2025-05-25 找出与y=x有交点的所有一元一次函数  已解决
2025-05-25 小结-从不缺考的学生  未解决
2025-05-25 小结-行转列,展开学生成绩(1)  已解决
2025-05-25 HAVING-语数英优异的学生  已解决
2025-05-25 HAVING-执教教师超过3人的科目  已解决
2025-05-25 HAVING-每次成绩都不低于80分的学生  已解决
2025-05-25 CASE WHEN-老中青教师数量  已解决
2025-05-25 CASE WHEN-男女学生的数量  已解决
2025-05-25 聚合函数-比较两位同学的数学成绩  已解决
2025-05-25 聚合函数-735011学生的语文成绩  已解决
2025-05-23 GROUP BY-各班级人数  已解决
2025-05-23 字符串函数-查找任教3个班级的所有教师  已解决
2025-05-23 字符串函数-查找任教5个班级的所有教师  已解决
2025-05-23 条件过滤-符合条件的班主任  已解决
2025-05-23 条件过滤-查找2009年出生的女学生  已解决
2025-05-23 数学成绩分段统计(1)  已解决
2025-05-22 化学老师的教学成果  已解决
2025-05-22 优异物理成绩的分布  已解决
2025-05-22 S1年级物理成绩前10名(2)  已解决
2025-05-22 抖音面试真题(1)T+1日留存率  未解决
2025-05-22 找出与X轴交点小于等于0的一元一次函数  已解决
2025-05-21 找出与X轴交点大于0的一元一次函数  已解决
2025-05-21 找出所有一元一次函数  已解决
2025-05-21 销售金额前10的商品信息  已解决
2025-05-21 A和K之间的手牌(3)  已解决
2025-05-21 A和K之间的手牌(2)  已解决
2025-05-21 大于J小于K的手牌  已解决
2025-05-21 语文数学英语至少1门超过100分的同学  已解决
2025-05-21 性别已知的听歌用户  已解决
2025-05-21 2000年以前出生的男歌手  已解决
2025-05-20 找出所有港台歌手  已解决
2025-05-20 表连接(2)渣男去过我对象没去过,那就用LeftJoin  已解决
2025-05-19 表连接(1)你们难道都去过?那就试试用InnerJoin  已解决
2025-05-19 条件过滤(1)异地男友有异常,数分闺蜜来帮忙  已解决
2025-03-21 S1年级物理成绩前10名(1)  已解决
2025-03-19 字符串与通配符(2)好多关键词做规则,可以使用rlike  未解决
2025-03-18 分类(1)姿势太多很过分,分类要用CaseWhen  已解决
2025-03-18 分组与聚合函数(6)想知道渣男有多坏,疯狂使用GroupBy  已解决
2025-03-17 分组与聚合函数(5)想知道何时成瘾,用Max Or Min?  已解决
2025-03-17 分组与聚合函数(5)五花八门的项目,其实都有固定套路(2)  已解决
2025-03-17 分组与聚合函数(2)擦边营收怎么样,聚合函数可看出  已解决
2025-03-15 条件过滤(3)Hour函数很给力,组合条件要仔细  已解决

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提交日期 题目名称 提交代码
2025-06-13 多云天气天数 
select
city,
COUNT(case when con LIKE '%多云%' THEN 1 ELSE null END) AS cloudy_days,
concat(CAST(COUNT(case when con LIKE '%多云%' THEN 1 ELSE null END)*100/dayofyear('2021-12-31') AS DECIMAL(10,2)), '%') AS p
from weather_rcd_china 
where YEAR(dt) = 2021
GROUP BY city
ORDER BY 3 DESC;
2025-06-13 多云天气天数 
select
city,
COUNT(case when con LIKE '%多云%' THEN 1 ELSE null END) AS cloudy_days,
CONCAT(round(COUNT(case when con LIKE '%多云%' THEN 1 ELSE null END)*100/dayofyear('2021-12-31'), 2), '%') AS p
from weather_rcd_china 
where YEAR(dt) = 2021
GROUP BY city
ORDER BY p DESC;
2025-06-13 城市平均最高气温 
select
city,
CAST(avg(tmp_h) as DECIMAL(4,2) )AS avg_tmp_h
FROM weather_rcd_china
WHERE year(dt)=2021
GROUP BY city
order by avg_tmp_h DESC;
2025-06-13 城市平均最高气温 
select
city,
ROUND(avg(CAST(substring_index(tmp_h, '℃', 1) AS DECIMAL(4,2))), 2) AS avg_tmp_h
FROM weather_rcd_china
WHERE year(dt)=2021
GROUP BY city
order by avg_tmp_h DESC
2025-06-13 城市平均最高气温 
select
city,
ROUND(avg(CAST(substring_index(tmp_h, '℃', 1) AS FLOAT)), 2) AS avg_tmp_h
FROM weather_rcd_china
WHERE year(dt)=2021
GROUP BY city
order by avg_tmp_h DESC
2025-06-13 城市平均最高气温 
select
city,
ROUND(avg(CAST(substring_index(tmp_h, '℃', 1) AS float)), 2) AS avg_tmp_h
FROM weather_rcd_china
GROUP BY city
order by avg_tmp_h DESC
2025-06-12 只买iPhone的用户 
SELECT user_id
FROM apple_pchs_rcd
GROUP BY user_id
HAVING COUNT(DISTINCT product_type) = 1 
 AND MAX(product_type) = 'iPhone'
2025-06-12 只买iPhone的用户 
select user_id from (
SELECT user_id
FROM apple_pchs_rcd
GROUP BY user_id
having 
	SUM(IF(product_type != 'iPhone', 1, 0)) =0
) as temp
order by user_id ASC;
2025-06-12 只买iPhone的用户 
select user_id from (
SELECT user_id,product_type
FROM apple_pchs_rcd
GROUP BY user_id, product_type
having 
	SUM(IF(product_type != 'iPhone', 1, 0)) =0
) as temp
order by user_id ASC;
2025-06-12 只买iPhone的用户 
SELECT user_id
FROM apple_pchs_rcd
GROUP BY user_id
having 
	SUM(IF(product_type != 'iPhone', 1, 0)) =0
order by user_id ASC;
2025-06-12 只买iPhone的用户 
select user_id from (
SELECT user_id, product_type
FROM apple_pchs_rcd
GROUP BY user_id, product_type
having 
	SUM(IF(product_type != 'iPhone', 1, 0)) =0
) as temp
order by user_id ASC;
2025-06-12 只买iPhone的用户 
select user_id from (
SELECT user_id, product_type
FROM apple_pchs_rcd
GROUP BY user_id, product_type
having 
	SUM(IF(product_type = 'iPhone', 1, 0)) =1
) as temp
order by user_id ASC;
2025-06-12 只买iPhone的用户 
select user_id from (
SELECT user_id, product_type
FROM apple_pchs_rcd
GROUP BY user_id, product_type
having COUNT(DISTINCT product_type) = 1 AND product_type = 'iPhone'
) AS temp
2025-06-12 只买iPhone的用户 
SELECT DISTINCT user_id
FROM (
SELECT user_id, product_name
FROM apple_pchs_rcd
WHERE product_type = 'iPhone'
) AS temp
GROUP BY user_id
HAVING COUNT(DISTINCT product_name) = 1
ORDER BY user_id ASC;
2025-06-12 只买iPhone的用户 
SELECT A.user_id 
FROM (
select
user_id,product_type
from apple_pchs_rcd
GROUP BY user_id, product_type
) AS A
LEFT JOIN (
select 
user_id,product_type
from apple_pchs_rcd 
WHERE product_type = 'iPhone'
GROUP BY user_id, product_type
) AS B
ON A.product_type = B.product_type AND A.user_id <> B.user_id
2025-06-12 基于共同兴趣爱好的餐厅推荐(6)-好基友(5) 
select 
A.cust_uid, B.cust_uid
from (
SELECT
cust_uid, mch_nm
from mt_trx_rcd1 
WHERE cust_uid='MT10000'
GROUP BY cust_uid, mch_nm
) as A 
LEFT JOIN (
select DISTINCT
cust_uid, mch_nm from mt_trx_rcd1
) as B
ON A.cust_uid <> B.cust_uid AND A.mch_nm = B.mch_nm
GROUP BY A.cust_uid, B.cust_uid
HAVING COUNT(DISTINCT A.mch_nm) >= 14
2025-06-12 基于共同兴趣爱好的餐厅推荐(6)-好基友(5) 
select 
A.cust_uid, B.cust_uid
from (
SELECT
cust_uid, mch_nm
from mt_trx_rcd1 
WHERE cust_uid='MT10000'
GROUP BY cust_uid, mch_nm
) as A 
LEFT JOIN (
select DISTINCT
cust_uid, mch_nm from mt_trx_rcd1
GROUP BY cust_uid, mch_nm
) as B
ON A.cust_uid <> B.cust_uid
2025-06-12 基于共同兴趣爱好的餐厅推荐(5)-好基友(4) 
select 
A.cust_uid, B.cust_uid
from (
SELECT
cust_uid, mch_nm
from mt_trx_rcd1 
WHERE cust_uid='MT10000'
GROUP BY cust_uid, mch_nm
) as A 
LEFT JOIN (
SELECT t2.cust_uid
FROM (
select DISTINCT
cust_uid, mch_nm from mt_trx_rcd1
where mch_nm = '庄家界(千灯店)'
GROUP BY cust_uid, mch_nm
) as t1
INNER JOIN (
select 
cust_uid, mch_nm from mt_trx_rcd1
where mch_nm = '黄记烘培宫廷桃酥王'
GROUP BY cust_uid, mch_nm
) as t2
ON t1.cust_uid = t2.cust_uid
INNER JOIN (
select 
cust_uid, mch_nm from mt_trx_rcd1
where mch_nm = '品众素心素食餐厅'
GROUP BY cust_uid, mch_nm 
) as t3
ON t1.cust_uid = t3.cust_uid
INNER JOIN (
select 
cust_uid, mch_nm from mt_trx_rcd1
where mch_nm = '一枚帅哥做的菜'
GROUP BY cust_uid, mch_nm
) as t4
ON t3.cust_uid = t4.cust_uid
) AS B
on A.cust_uid <> B.cust_uid
group by A.cust_uid , B.cust_uid
order by A.cust_uid, B.cust_uid
2025-06-12 基于共同兴趣爱好的餐厅推荐(5)-好基友(3) 
select 
A.cust_uid, B.cust_uid
from (
SELECT
cust_uid, mch_nm
from mt_trx_rcd1 
WHERE cust_uid='MT10000'
GROUP BY cust_uid, mch_nm
) as A 
LEFT JOIN (
SELECT t2.cust_uid
FROM (
select DISTINCT
cust_uid, mch_nm from mt_trx_rcd1
where mch_nm = '庄家界(千灯店)'
GROUP BY cust_uid, mch_nm
) as t1
INNER JOIN (
select 
cust_uid, mch_nm from mt_trx_rcd1
where mch_nm = '黄记烘培宫廷桃酥王'
GROUP BY cust_uid, mch_nm
) as t2
ON t1.cust_uid = t2.cust_uid
INNER JOIN (
select 
cust_uid, mch_nm from mt_trx_rcd1
where mch_nm = '品众素心素食餐厅'
GROUP BY cust_uid, mch_nm 
) as t3
ON t1.cust_uid = t3.cust_uid
) AS B
on A.cust_uid <> B.cust_uid
group by A.cust_uid , B.cust_uid
order by A.cust_uid, B.cust_uid
2025-06-12 基于共同兴趣爱好的餐厅推荐(5)-好基友(3) 
select 
A.cust_uid, B.cust_uid
from (
SELECT
cust_uid, mch_nm
from mt_trx_rcd1 
WHERE cust_uid='MT10000'
GROUP BY cust_uid, mch_nm
) as A 
LEFT JOIN (
SELECT t2.cust_uid
FROM (
select DISTINCT
cust_uid, mch_nm from mt_trx_rcd1
where mch_nm = '庄家界(千灯店)'
GROUP BY cust_uid, mch_nm
) as t1
INNER JOIN (
select 
cust_uid, mch_nm from mt_trx_rcd1
where mch_nm = '黄记烘培宫廷桃酥王'
GROUP BY cust_uid, mch_nm
) as t2
ON t1.cust_uid = t2.cust_uid
INNER JOIN (
select 
cust_uid, mch_nm from mt_trx_rcd1
where mch_nm = '黄记烘培宫廷桃酥王'
GROUP BY cust_uid, mch_nm 
) as t3
ON t1.cust_uid = t3.cust_uid
) AS B
on A.cust_uid <> B.cust_uid
group by A.cust_uid , B.cust_uid
order by A.cust_uid, B.cust_uid