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勋章 ①金银铜:在竞赛中获得第一二三名;②好习惯:自然月10天提交;③里程碑:解决1/2/5/10/20/50/100/200题;④每周打卡挑战:完成每周5题,每年1月1日清零。

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收藏日期 题目名称 解决状态
2026-04-02 上月活跃用户数  未解决
2026-04-02 一线城市历年平均气温  未解决
2026-04-02 冬季下雪天数  已解决
2026-04-02 滴滴面试真题(2)打车订单呼叫应答时间  已解决
2026-04-01 条件过滤(3)Hour函数很给力,组合条件要仔细  已解决
2026-03-31 HAVING-每次成绩都不低于80分的学生  未解决

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提交日期 题目名称 提交代码
2026-04-14 数学成绩分段统计(1) 
SELECT 
    CASE 
        WHEN sc.score >= 110 THEN '[110, 120]'
        WHEN sc.score >= 90 THEN '[90, 110)'
        WHEN sc.score >= 60 THEN '[60, 90)'
        ELSE '[0, 60)'
    END AS score_range,
    COUNT(*) AS num_students
FROM 
    students s
JOIN 
    scores sc ON s.student_id = sc.student_id
WHERE 
    sc.subject = '数学' 
    AND sc.exam_date = '2024-06-30'
GROUP BY 
    score_range
ORDER BY 
    score_range DESC;
2026-04-14 数学成绩分段统计(1) 
select case when score >=110 then '[110, 120)'
when score>=90 and score<110 then '[90, 110)' 
when score>=60 and score<90 then '[60, 90)'
else '[0, 60)'
end as score_range, count(*) as num_students
FROM 
    scores sc where sc.subject='数学' and sc.exam_date='2024-06-30' GROUP BY 
    score_range
ORDER BY 
    score_range DESC;
2026-04-14 数学成绩分段统计(1) 
select case when score >=110 then '[110,120)'
when score>=90 and score<110 then '[90,110)' 
when score>=60 and score<90 then '[60,90)'
else '[0,60)'
end as score_range, count(*) as num_students
FROM 
    scores sc where sc.subject='数学' and sc.exam_date='2024-06-30' GROUP BY 
    score_range
ORDER BY 
    score_range DESC;;
2026-04-14 不分类别的最火直播间 
select a.*,b.live_nm from 
(select live_id,count(distinct usr_id) from ks_live_t1 where DATE_FORMAT(enter_time,'%Y-%m-%d %H')='2021-09-12 23' group by live_id) a join 
(select * from ks_live_t2) b on a.live_id=b.live_id order by 2 desc;
;
2026-04-14 表连接(2)渣男去过我对象没去过,那就用LeftJoin 
select b.mch_nm as asshole_tried, b.trx_cnt,a.mch_nm as darling_tried 
from (select distinct mch_nm from cmb_usr_trx_rcd where (year(trx_time) between 2023 and 2024) and usr_id='5211314521') a 
right join
(select distinct mch_nm,count(1) trx_cnt from cmb_usr_trx_rcd where (year(trx_time) between 2023 and 2024) and usr_id='5201314520' group by mch_nm having count(mch_nm)>=20) b
on a.mch_nm = b.mch_nm order by 2 desc;
2026-04-14 表连接(1)你们难道都去过?那就试试用InnerJoin 
SELECT cm.* 
FROM (
SELECT distinct mch_nm 
FROM cmb_usr_trx_rcd 
WHERE YEAR(trx_time) = 2024 AND usr_id = '5211314521'
) AS cm
JOIN (
SELECT distinct mch_nm 
FROM cmb_usr_trx_rcd 
WHERE YEAR(trx_time) = 2024 AND usr_id = '5201314520'
) AS c
ON cm.mch_nm = c.mch_nm;
2026-04-14 HAVING子句中的子查询 
select mch_nm,sum(trx_amt) from cmb_usr_trx_rcd group by mch_nm having SUM(trx_amt) > 10 *(select avg(trx_amt) from cmb_usr_trx_rcd);
2026-04-14 NOT IN子查询 
SELECT *
FROM cmb_usr_trx_rcd
WHERE usr_id NOT IN (
    SELECT DISTINCT usr_id
    FROM cmb_usr_trx_rcd
    WHERE mch_nm = '肯德基'
);
2026-04-14 IN子查询 
SELECT * FROM cmb_usr_trx_rcd
WHERE usr_id IN (
    SELECT usr_id
    FROM cmb_usr_trx_rcd
    WHERE mch_nm = '肯德基'
)
ORDER BY usr_id, trx_time;
2026-04-14 IN子查询 
select * from cmb_usr_trx_rcdwhere usr_id in (select usr_id from cmb_usr_trx_rcd where mch_nmlike '%肯德基%');
2026-04-14 IN子查询 
select * from cmb_usr_trx_rcd c where usr_id in (select usr_id from cmb_usr_trx_rcd where c.mch_nmlike '%肯德基%');
2026-04-14 WHERE子查询 + 比较运算符 
select * from cmb_usr_trx_rcd where trx_amt>(select avg(trx_amt) from cmb_usr_trx_rcd);
2026-04-14 基础标量子查询-不带分组 
select usr_id,
    mch_nm,
    trx_time,
    trx_amt, 
(select avg(trx_amt) from cmb_usr_trx_rcd)
from cmb_usr_trx_rcd where usr_id='5201314520';
2026-04-14 基础标量子查询-带分组 
select usr_id,
	sum(trx_amt) as total_amt,
(select avg(trx_amt) from cmb_usr_trx_rcd) as avg_amt 
from cmb_usr_trx_rcd 
group by usr_id;
2026-04-14 字符串与通配符(2)好多关键词做规则,可以使用rlike 
select
    case 
        when mch_nm like '%按摩保健休闲%' then '按摩保健休闲'
        when mch_nm rlike '.*(按摩|保健|休闲|spa|养生|会所).*' then '按摩、保健、休闲、养生、SPA、会所'
    end as reg_rules,
    count(distinct mch_nm) as mch_cnt
from
    cmb_usr_trx_rcd
where mch_nm like '%按摩保健休闲%'
   or mch_nm rlike '.*(按摩|保健|休闲|spa|养生|会所).*'
group by reg_rules
order by mch_cnt desc;
2026-04-14 字符串与通配符(1)名称里面有特服,可以使用通配符 
select count(distinct mch_nm) from cmb_usr_trx_rcd where mch_nm like '%按摩保健休闲%';
2026-04-14 字符串与通配符(1)名称里面有特服,可以使用通配符 
select count(*) from cmb_usr_trx_rcd where mch_nm like '%按摩保健休闲%';
2026-04-02 冬季下雪天数 
select city, sum(case when con like '%雪%' then 1 else 0 end) as snowdays from weather_rcd_china where month(dt) in (12,1,2) group by city order by 2 desc;
2026-04-02 冬季下雪天数 
select city,count(1) as snowdays from weather_rcd_china where con like '%雪%' and month(dt) in (12,1,2) group by city order by snowdays desc;
2026-04-02 冬季下雪天数 
select city,count(1) as snowdays from weather_rcd_china where con like '%雪%' and month(dt) in (12,1,2) group by city;